Difference between revisions of "Print Numbers"
From CompSciWiki
| Line 13: | Line 13: | ||
|SideSection= | |SideSection= | ||
| + | <BR> | ||
|Solution= | |Solution= | ||
| − | You should split this up into three methods which print out the smallest, middle and largest | + | You should split this up into three methods which print out the smallest, middle and largest numbers. |
<pre> | <pre> | ||
public static void printSmallest( int n1, int n2, int n3 ); | public static void printSmallest( int n1, int n2, int n3 ); | ||
| − | public static void | + | public static void printMidNum( int n1, int n2, int n3 ); |
public static void printLargest( int n1, int n2, int n3 ); | public static void printLargest( int n1, int n2, int n3 ); | ||
</pre> | </pre> | ||
| Line 39: | Line 40: | ||
} | } | ||
</pre> | </pre> | ||
| + | and similarly for the middle and largest numbers. | ||
|SolutionCode= | |SolutionCode= | ||
<pre> | <pre> | ||
| − | public static void | + | public static void printNumbers( int n1, int n2, int n3 ) |
{ | { | ||
| − | + | printSmallest(); | |
| + | System.out.print( "," ); | ||
| + | printMidNum(); | ||
| + | System.out.print( "," ); | ||
| + | printLArgest(); | ||
| + | } | ||
| + | |||
| + | public static void printSmallest( int n1, int n2, int n3 ) | ||
| + | { | ||
| + | if( n1 <= n2 && n1 <= n3 ) | ||
{ | { | ||
| − | + | System.out.print( n1 ); | |
| + | } | ||
| + | else if( n2 <= n3 ) | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
| + | } | ||
| + | else | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
} | } | ||
} | } | ||
| + | |||
| + | public static void printMidNum( int n1, int n2, int n3 ) | ||
| + | { | ||
| + | if( n1 >= n2 && n1 <= n3 ) | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
| + | } | ||
| + | else if( n2 >= n1 && n2 <= n3 ) | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
| + | } | ||
| + | else | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
| + | } | ||
| + | } | ||
| + | |||
| + | public static void printLargest( int n1, int n2, int n3 ) | ||
| + | { | ||
| + | if( n1 >= n2 && n1 >= n3 ) | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
| + | } | ||
| + | else if( n2 >= n3 ) | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
| + | } | ||
| + | else | ||
| + | { | ||
| + | System.out.print( n1 ); | ||
| + | } | ||
| + | } | ||
| + | |||
</pre> | </pre> | ||
}} | }} | ||
Revision as of 12:48, 6 April 2010
Back to the Program-A-Day homepage
ProblemWrite a method which will take 3 ints as parameters.
The method should print the elements of the array in order, separated by a comma.
|
...by students
| |
|---|---|---|
SolutionYou should split this up into three methods which print out the smallest, middle and largest numbers. public static void printSmallest( int n1, int n2, int n3 ); public static void printMidNum( int n1, int n2, int n3 ); public static void printLargest( int n1, int n2, int n3 ); You will need to use if statements to determine the proper order to print out the numbers.
if( n1 <= n2 && n1 <= n3 )
{
System.out.print( n1 );
}
else if( n2 <= n3 )
{
System.out.print( n1 );
}
else
{
System.out.print( n1 );
}
and similarly for the middle and largest numbers. | ||
Code | ||
