Difference between revisions of "Leap Year Problem"

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Line 31: Line 31:
 
         boolean done = false;
 
         boolean done = false;
 
          
 
          
 +
        //keep executing this until we're done (user cancels)
 
         while( !done )
 
         while( !done )
 
         {
 
         {
 +
            //get the input from the user
 
             input = JOptionPane.showInputDialog( "Enter a year:" );
 
             input = JOptionPane.showInputDialog( "Enter a year:" );
 
              
 
              
Line 52: Line 54:
 
                 }
 
                 }
 
             }
 
             }
             else
+
             else //the user canceled
 
                 done = true;
 
                 done = true;
 
             }
 
             }

Revision as of 23:15, 5 April 2010

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Problem

Write a short program that takes a year as input from the user, and then determines whether or not that particular year is (or was) a leap year. Your program should keep asking for more years until the user enters something non-numeric, or clicks 'Cancel' on the input box.

As a reminder, here is the criteria that dictates whether or not a year is a leap year: If the year is evenly divisible by 4, then the year is a leap year -- unless it is also divisible by 100, in which case it is not. An exception to this is if the year is divisible by 400, then it is still a leap year.

Examples:
1996 was a leap year because it was divisible by 4.
1900 was not a leap year in spite of being divisible by 4, because it is also divisible by 100.
2000 was a leap year because it is divisible by 400.
2009 was not a leap year, because it is not divisible by 4.

 

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