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Problem
Esperanto
Esperanto is a language invented in the 1880s by L. L. Zamenhof. It was invented to "create an easy-to-learn and politically neutral language that would serve as a universal second language to foster peace and international understanding."
One of the benefits of designing your own language is that you can impose strict rules on the language. In this question, you will use the rules of Esperanto to identify the parts of speech of different words. The rules for identifying parts of speech in Esperanto are:
| If the word ends in .. |
it is a(n)... |
| a | adjective |
| o or on | singular noun |
| oj or ojn | plural noun |
| e | adverb |
This means there are no exceptions in Esperanto, like how in English the plural of goose is geese and while you usually add 'ly' to the end of an adjective to make it an adverb, 'goodly' isn't an adverb.
Write a program that accepts words in Esperanto, and identifies whether each is an adjective, singular noun, plural noun or adverb. Input: Use Scanner to accept input in this question. Prompt the user to input a word. If the user types in "cesi" ("quit" in Esperanto), the program should quit. Otherwise, it should accept the input and process it as a word in Esperanto. After processing the word, the user should be prompted to enter another word. Assume the user inputs the words entirely in lowercase and that all words are at least three letters long. Calculate and Output: Use System.out. for all output. Use the charAt() and length() methods to find the last (one or possibly two) characters and determine which part of speech (adverb, singular noun, plural noun or adverb) the word is. If the word is in none of the four categories, print out an error message telling the user that the part of speech cannot be identified. An execution of your program would look like this:
Enter a word in Esperanto: komputilo
komputilo is a singular noun.
Enter a word in Esperanto: sciencon
sciencon is a singular noun.
Enter a word in Esperanto: cesi
Programmed by [your name here].
End of processing.
- Organize the code.
- Add comments to explain the code.
- Optimize the code by removing unnecessary variables.
- Find any errors in the code.
- Add code to output progress reports as the program executes.
Remember to abide by the company coding standards while repairing the code.
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Esperanto
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Solution
ENTER SOLUTION
There are nine steps to improve this messy code so it complies with the company (and coincidentally, comp 1010) coding standards:
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Code
Solution Code
import java.util.Scanner;
/**
* A2Q2 -
*
* COMP 010 Section A00
* INSTRUCTOR
* ASSIGNMENT 2, Question 2
* @author 1010
* @version 2010-Oct-18
*
* PURPOSE: calculates the decimal version of a binary number.
*/
public class A2Q2
{
public static void main(String[] args)
{
Scanner kbd = new Scanner(System.in);
long binaryNumber, copyOfBinNum; // input from the user.
int decimalNumber; // output value.
final int BASE = 2; // binary base.
int currDigit, currPower; // values used in loops.
// get input from the user.
System.out.print("Enter a binary number:");
binaryNumber = kbd.nextLong();
// keep looping until -1 is encountered.
while (binaryNumber != -1)
{
// reset values to 0, use copyOfBinNum for calculations.
decimalNumber = 0;
currPower = 0;
copyOfBinNum = binaryNumber;
// keep looping until all digits of copyOfBinNum are removed.
while (copyOfBinNum > 0)
{
// get last digit and strip it off copyOfBinNum
currDigit = (int) copyOfBinNum % 10;
copyOfBinNum /= 10;
// add to the running total if the digit is one
if (currDigit == 1)
{
decimalNumber += Math.pow(BASE,currPower);
}
// increment the power of two for next loop.
currPower++;
}
// output the right decimal value.
System.out.println(binaryNumber + " in decimal is " + decimalNumber + ".");
// get ready for next iteration of the loop.
System.out.print("Enter a binary number:");
binaryNumber=kbd.nextLong();
}
System.out.println("Programmed by [your name here].");
System.out.println("End of processing.");
}
}
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