Creating an Array
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ProblemThere are ten students with ten grades. Instead of storing every single grade in a single variable it is easier to store this information in an array. The grades of the ten students are 56%, 34%, 75%, 89%, 78%, 87%, 71%, 67%, 98%, 85%. Do the following:
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Introducing Array | |
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SolutionFirst create the skeleton structure of your program public class CreatingArray{
public static void main(){
}
}
Next, the two arrays to be used are integer and double, so we need to create the variables that will store these arrays. int[] intArray; double[] decimalArray; String[] stringArray; These will go inside the main program. Now a new array must be created, this is done with the new keyword. intArray = new int[10]; decimalArray = new double[10]; stringArray = new String[10]; The 10 specifies the size of the array that you want to create. Now we will need to store the values inside the array. This is done by equating each position within the array with they value we want to store. intArray[0] = 56; decimalArray[0] = intArray[0]/100.0; // or decimalArray[0] = 0.56; stringArray[0] = "Bill"; intArray[1] = 34; decimalArray[1] = 0.34; stringArray[1] = "Bob"; etc. If the numbers that you are entering are known before hand, as in this case, it's much faster to create the array in short hand format. This is done by creating your array variable and immediately assigning a list of values to it. This will automatically create the new array of the required size and initialize elements in the array to the appropriate value. This short hand for the first 3 numbers or strings will look like this: int[] intArray;
intArray = {56, 34, 75};
String[] stringArray;
stringArray = {"Bill", "Bob", "Betty"};
This can also be done in one line. int[] intArray = {56, 34, 75};
String[] stringArray = {"Bill", "Bob", "Betty"};
All that needs to be done now is to create the three arrays for the grades. | ||
Code | ||
