Fibonacci sequence

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Problem

Write a complete Java program titled Fibonacci that:

  • prompts the user to enter an input number and casts it to integer
  • gets the nth fibonacci number using a for loop, based on the user's input
  • prints out the nth fibonacci number, using JOptionPane method.


Note that the fibonacci sequence is <math>F(0) = 1, F(1) = 1, F(n) = F(n-1) + F(n-2) for n > 1</math>.
Example: <math>F(5) = 1, 1, 2, 3, 5, 8</math>
Your output should look something like
"The 5th number of the fibonacci sequence is 5."

You may assume that the user always enters correct integer format.

 

...By students

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First, always write comments. This may depend on each student's skill, but most students won't finish their code or assignments in few hours. The reason is because when you work on it later, you are very likely to forget what you were doing. Writing comments will help you remember what you were doing and it will be easier for you to fix errors when going through your code.
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Solution

In order to get user input from JOptionPane you will need to import the swing package.
You can import swing package by

 import javax.swing.*; 

or

 import javax.swing.JOptionPane; 


The next step is declaring variables.
In this program we will need three integer variables.
One variable will be used as <math>F(n)</math> and another variable will be used as <math>F(n-1)</math>.
Our initial value for <math>F(n)</math> will be 1 and <math>F(n-1)</math> will be 0, referring to the fibonacci formula.
<math>F(0) = 1, F(1) = 1</math>

Once you declare the necessary variables, the last variable will be the casted integer from the user input.

 int n = 1
int n-1 = 0
String str = get the user input using JOptionPane
int input = cast str to integer 


Once you have all the variables ready, make a for loop that starts from 0 and ends when the counter is less than n (user input).
In this for loop, the increment will be 1.

 for(count = 0; count < user input; count increment by 1)
{
} 


We will need another variable to keep track of <math>F(n-2)</math>.
You simply set it <math>F(n-2) = F(n-1)</math> as it starts a new iteration, and set <math>F(n-1) = F(n)</math>.
Then sum up the <math>F(n-2) + F(n-1)</math> which will now be <math>F(n)</math>.

<math>(n-2) = (n-1)</math>

<math>(n-1) = n</math>

<math>n = (n-2) + (n-1)</math>

When the for loop ends, you will have the nth fibonacci number.
At last, print it out using JOptionPane.

 JOptionPane.showMessageDialog(null, "The " + n + "th Fibonacci number is " + current); 


When you are printing the result out with JOptionPane, note that you have to put 'null' before the actual message you want to print out.

This problem was the review of 'While and For Loops'.
See below for the solution code.

Code

Solution Code

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