Difference between revisions of "Print Numbers"
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(printLArgest(); to printLargest();) |
(All your doing is printing n1....) |
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else if( n2 <= n3 ) | else if( n2 <= n3 ) | ||
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− | System.out.print( | + | System.out.print( n2 ); |
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else | else | ||
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else if( n2 >= n1 && n2 <= n3 ) | else if( n2 >= n1 && n2 <= n3 ) | ||
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− | System.out.print( | + | System.out.print( n2 ); |
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else | else | ||
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else if( n2 >= n3 ) | else if( n2 >= n3 ) | ||
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else | else | ||
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− | System.out.print( | + | System.out.print( n3 ); |
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Revision as of 12:45, 8 April 2010
Back to the Program-A-Day homepage
ProblemWrite a method which will take 3 ints as parameters.
The method should print the elements in order, separated by a comma.
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Static Methods
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SolutionYou should split this up into three methods which print out the smallest, middle and largest numbers. public static void printSmallest( int n1, int n2, int n3 ); public static void printMidNum( int n1, int n2, int n3 ); public static void printLargest( int n1, int n2, int n3 ); You will need to use if statements to determine the proper order to print out the numbers. if( n1 <= n2 && n1 <= n3 ) { System.out.print( n1 ); } else if( n2 <= n3 ) { System.out.print( n1 ); } else { System.out.print( n1 ); } and similarly for the middle and largest numbers. | ||
Code |