Problem

Write a method which will take 3 integers as parameters. The method should print out the elements in order from smallest to largest, separated by a comma.

For example, if the numbers input by the user are 40, 32, and 11, the program would have this output:

 Enter the first number: 
 40
Enter the second number: 
 32
Enter the third number: 
 11
Numbers: 11, 32, 40

Programmed by A. Student
**End of Program** 

Static Methods

Solution

You should split this up into three methods which print out the smallest, middle and largest numbers.

 public static void printSmallest( int n1, int n2, int n3 );
public static void printMidNum( int n1, int n2, int n3 );
public static void printLargest( int n1, int n2, int n3 ); 

You will need to use if statements to determine the proper order to print out the numbers.

 if( n1 <= n2 && n1 <= n3 )
{
   System.out.print( n1 );
}
else if( n2 <= n3 )
{
   System.out.print( n2 );
}
else
{
   System.out.print( n3 );
} 

and similarly for the middle and largest numbers.

Code

Solution Code

public static void printNumbers( int n1, int n2, int n3 )
{
   printSmallest( n1, n2, n3 );
   System.out.print( "," );
   printMidNum( n1, n2, n3 );
   System.out.print( "," );
   printLargest( n1, n2, n3 );
}

public static void printSmallest( int n1, int n2, int n3 )
{
   if( n1 <= n2 && n1 <= n3 )
   {
      System.out.print( n1 );
   }
   else if( n2 <= n3 )
   {
      System.out.print( n2 );
   }
   else
   {
      System.out.print( n3 );
   }
}

public static void printMidNum( int n1, int n2, int n3 )
{
   if( n1 >= n2 && n1 <= n3